Why the output of the program is "4, 4, 8, 1"???

Question

#include <stdio.h>

int main() {
printf("int: %d \n", sizeof(int));
printf("float: %d \n", sizeof(float));
printf("double: %d \n", sizeof(double));
printf("char: %d \n", sizeof(char));

return 0;
}

Answer 1

Ok thank you bro
Niek Aukes

Answer 2

Niek Aukes plz can you answer me in detail. Thank you😊

Answer 3

Well, an int takes 4 bytes in the memory, double takes 8 bytes. Its measuring the size of the data. Mostly you won't use it much since current memory is at least more than a gigabyte

Answer 4

Niek Aukes
As far as I know, int requires 2 bytes?

Answer 5

Int- 4 bytes
float - 4 bytes
double - 8 bytes
Char - 1 byte

If you were asking something else, leave a reply

Answer 6

Vaibhav I think you mean short ints, they require 2 bytes, but can't surpass the number 32768 since all bits are used

Answer 7

But if not mentioned,
sizeof(int) will give as 2

Answer 8

#include <stdio.h>

int main() {
printf("int: %d \n", sizeof(int));
printf("short: %d \n", sizeof(short));

return 0;
}

Int: 4
Short: 2
Vaibhav highly doubt it