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Why is "elif x == ("2"):" - IdentitationError???
elif x == ("2"): print("\n Welcome! \nThis is a IPGETTER. The Most speedfull app for check the IP of Host") print("\n***************************CMD******************************") y = input("\nEnter Hostname: ") hostname = y IP = socket.gethostbyname(y) print("Succes!") print(IP)
5 ответов
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People can't copy and paste text in questions so please link the code so we can look at it better
+ 1
I think you didn't put any space before:
y = input....
hostname = y
IP = socke...
print("Suc...
print(IP)
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i havent publish it. i write it here
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import random
import socket
guest = ""
password = "Joker-Tool"
print("This is Joker-Tool coded by Joe or CMD")
while guest != password:
guest = input("\nPlease enter a password to use this Tool: ")
if guest == password:
print("\nSucces!")
print("\n~")
print("\nOptions: [1] Random Love, [2] IPGetter, [3] Random number")
x = input("Select your option, please: ")
while x == ("1"):
list = ["Nava", "Paula", "Lou"]
print("You love " + random.choice(list))
else:
print("Error")
elif x == ("2"):
print("\n Welcome! \nThis is a IPGETTER. The Most speedfull app for check the IP of Host") print("\n***************************CMD******************************")
y = input("\nEnter Hostname: ")
hostname = y
IP = socket.gethostbyname(y)
print("Succes!")
print(IP)
elif x == ("3"):
nums = ["1", "2", "3", "4", "5", "6"]
print("Your number is: " + random.choice(nums))
else:
print("Error")
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Joe Don't start with elif but if.
If your editor can do this, highlight tabs or spaces. Maybe there is small difference, I can't find in the playground.
Daniele Bonomi Are you using the App? Then you could copy and paste the code in question by tapping at the three dots on the upper right and "Copy Text"