please i need help on how the answer to this question is 300

Question

def f(n):
if n==0:
return 0
else:
return f(n-1) + 100
print(f(3))

Answer 1

n=0, f(0)=0
n=1, f(1)= f(0) + 100 = 0 + 100 =100
n=2, f(2)=f(1) + 100 = f(0) + 100 + 100 = 200
n=3, f(3)=f(2) + 100 = f(1) + 100 +100 = f(0) +100 + 100 +100 = 300
result is 300

Answer 2

f(3) = f(2) + 100
f(2) = f(1) + 100
f(1) = f(0) + 100
f(0) = 0

then going back and resolving (f(0) is yet resolved to 0):

f(1)= 0+100= 100
f(2)= 100 + 100= 200
f(3)= 200+100= 300

Answer 3

thanks man

Answer 4

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