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what is" numpy.random.random_intrgers" do? i read about it in scipy.org but couldn't understand
9 ответов
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numpy.random.random_integers(1, 10)
would return an integer between 1 and 10 (both inclusive) chosen randomly. So we don't exactly know what the output will be, but it must something in the set {1,2,...,10}.
All that stuff about discrete uniform distribution means that the probability of it picking each integer in the range is the same. So, since there are 10 numbers in 1-10, on an average, each number will be picked one-tenth of the time.
By the way, the documentation also says that we are encouraged to use numpy.random.randint
instead. It is similar, but output of randint(1,10) is an integer between 1 and 9. 10 is not included this time, just like range() in Python.
Is there anything specific that you don't understand? I'll be happy to explain in more detail.
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My pleasure! I actually learnt about this function while trying to answer your question. So, thank YOU! 😊 Please feel free to ask more questions!
And good luck on your exam, I'm sure you'll do great!
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Actually, my previous answer is not complete. There is an optional argument which may be really useful in creating random arrays. Consider
numpy.random.random_integers(1, 10, (2,3))
This would create an array of size 2x3 (so 2 rows, 3 columns), and the entries of the array will be those random numbers between 1 and 10 (inclusive).
Similarly for randint, but just like before, the number 10 will not be included this time.
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thanks^^ so the answer (by example ) array([[3,6,1],
[4,2,2],
[9,0,1]])
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Yes, that would be the answer if I had (3,3) as the size argument, since you have 3 rows and 3 columns. For (2,3), it'd look like
[[2,9,7],
[4,1,6]]
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thank youuu! its very clear now😆
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we just learnt numpy two days ago and have python exam next week! thank for help ;)
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its hard
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Jess Mole not at all;)