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why i keep getting the same output
why i keep getting the same output in the case even though its suppose to have different answer/output the coding: #include<stdio.h> int main() { int t, n, m, o, c=0; scanf ("%d", &t); //for how many times input will be done while (c<t) { //for how many times input will be done scanf ("%d", &n); c++;} for (int d=0; d<t; d++) { m=n/365; o=m/4; printf ("Case #%d :\n%d\n",d+1, o+1); } } the output: 3 1 100 1460 // until here is input Case #1: // from here is output 2 // the answer supposed to be 1 Case #2 : 2 // this answer also 1 Case #3 : 2 // only this that the answer is true
2 ответов
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Because you read all three n values before you calculate the output, n is 1460 for all three outputs. If you want to read them all, you must have three different places to store them.
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thanks for the answer :)