Assigning multiple characters to an integer in C.

Question

#include<stdio.h>
void main(void)
{
int a='dd';
printf("%d ",a);
}

//OUTPUT : 25700
//For explanation do ping 😊

Answer 1

Yes, it happened because of the property of SINGLE QUOTE , which splits it's string into characters in a concatenation fashion.

for eg 'deep' is same as d concatenated with e , and e concatenated with other e and other e with p.

In above example 'dd' was splited as d d , thus in their binary representation as ( 01100100 01100100 ) and as a whole they sum up to 2^14 + 2^13 + 2^10 + 2^6 + 2^5 + 2^2 = 25700 in decimal. 😊

Answer 2

I didn't even know that was valid code, but it turns out it is implementation defined:
https://stackoverflow.com/a/26086630/514145

As for the value 25700, I do believe it comes from the fact that the letter 'd' has an ASCII encoding equal to 0x64, in binary 01100100.
I think that in the implementation you're using it just interprets the bit pattern corresponding to two 'd' as an integer, indeed the value:
0110010001100100 (the bit pattern above replicated two times) gives 25700 when interpreted as a decimal number