What is defect in this program?

Question

while true :
print("options :")
Print("enter'add'to add two numbers")
Print("enter'subtract'to subtract two numbers")
Print("enter'quit'to end the program")
users_input= input(":")
if user_input= 'add':
num1= float(input("entera number"))
num2 = float(input("enter another number"))
result= str(num1+num2)
print("the answer is + result")
elif user_input= "subtract":
num1= float(input("enter a number"))
num2= float(input("enter another number"))
result= (num1- num2)
print("the answer is + result")
elif user_input= 'quit':
print ("end the program")

Answer 1

Looks like you're ignoring indentation completely.

Wrong:
if condition:
do_something()

Correct:
if condition:
do_something()

Also, note that python is case sensitive. It's 'print', not 'Print'.

The comparison operator is ==, not = (if condition == True)

Answer 2

thanks

Answer 3

Also when you are trying to include a variable into a print statement you need to be careful where the " are and convert your variable type to a string:

print("the answer is " + str(result))