Help

Question

x=4
y=2
if not 1+1==y or x==4 and 7==8:
print ("yes")
elif x>y:
print ("No")
here in order to print yes three conditions are given.... i expect two conditions... because the boolean logic compares only two conditions...and what is the output..
plis help me in detail

Answer 1

well I think 1+1=y is true ,x=4 is true 7==8 is false the precedence order follows like this:
not((true)or(true and false))
=not true= false

Answer 2

Remember not means "not true", and a False output continues the code.
So for example not 1==1 would give a False output.

x=4
y=2
if not 1+1==y or x==4 and 7==8: <== (false, false, and false...continue code)
print ("yes")
elif x>y: <==(4>2, true, so 'No' prints)
print ("No")

line 3 reads if not 1+1==y or x==4 and 7==8:
so if 1+1==y is not true (2==2) is false, or x is not true (4==4) is also false.
And if 7==8 is not true (which is false) print 'yes' but all 3 are false.

I hope this helps!

Answer 3

X = 4 and y = 2 , the spaces count

Answer 4

... Can't you just run the code?

Answer 5

no is the answer

Answer 6

no answare

Answer 7

not((true)or(true and false))
=>not true= false

Answer 8

What's the output of this code?

print(7 != 8)

Answer 9

What's the output of this code?

print(7 != 8)

Answer 10

copy and run this code in the playground gives the answer straight away. so what is it you dont understand exactly? (are you confused about the code?)