The reversed number Recursively

Question

Hello SoloLearn! I am strugling with a problem if I may ask: How can i print the reversed number of n using a recursive function. I need it to return the reversed number through the name of the function (not using a variable).This is my attempt, but it returns the exact same number :)

#include <iostream>
#include <math.h>

using namespace std;

int oglindit(int n){

if(n<10)
return n;
else

return oglindit(n/10)*10+(n%10);

}

int main()
{

int n;
cin>>n;
cout<<oglindit(n);

return 0;
}

Thank you for your time!

Answer 1

https://code.sololearn.com/ceXQYEcj1D78/#cpp

Answer 2

return (n%10)*pow(10, (int)log10(n)) + oglindit(n/10);

Answer 3

Bennet Post
Thank you for the help, but I was looking for a solution that does not use another variable. Thank you for your time, I really apreciate it.

Answer 4

Mert Yazici
Thank you very much, it is working. I appreaciate your time.

Answer 5

Prokopios Poulimenos
Thank you very much, it is working. It is a bit hard to understand , but I will do my best to not memorize it but to understand it. I appreaciate the help.