code question

Question

What is the output of this code?
List<Integer> list = new ArrayList<Integer>();
list.add(10);
list.add(20);
list.add(30);
Iterator<Integer> it = list.iterator();
it.next();
System.out.println(it.next());

why the ans is 20??
is the ans wrong??

Answer 1

@bullion is right. Every time you call the it.next() method, it iterates through the list internally that is why you get 20 instead of 10.

Answer 2

https://www.sololearn.com/learn/Java/2184/?ref=app

Answer 3

No,
It points to 10 when declared
The first next
- return 10
- move pointer to 20
The second next
- return 20
- move pointer to 30

Answer 4

First call to it.next() makes the iterator point to 10.
The second call, inside println, makes it point to 20 and it is printed

Answer 5

5題題目的選擇過程，唔會俾錯的答案入到問題庫的