Plz give me step by step execution of pgm given

Question

main()
{ int i=1;
for(;i<6;I+=2){
i=i*i;
cout<<i ;}
}

Answer 1

In the 'for' parenthesis you write:
(;i<6;I+=2)

I guess the lowercase "L" is a typing error? And we must read "i"... else your loop is an infinite loop, because the condition ( i<6 ) is always true: in the body loop, only the i=i*i; is apt to modify the value, but don't ever change since is initialized with the value of 1 ( and 1 times 1 equals... 1 ).

So, if the "i" is really updated in incrementation part of the 'for' parenthesis:
- on start of 2nd iteration, i=1+2 == 3 ( at end of the 1st iteration ), so condition still true,
- loop is executed: i=3*3 == 9, '9' is printed.
- end of the loop, i=9+2 == 11
- start of 3rd iteration, i == 11 < 6, so loop is no more executed

Answer 2

Yes, on first iteration i value is 1 and is printed.
Print don't append a new line to the output, so the output is well 19 ( not '19', but '1' nexted by '9' ;) )

Answer 3

thank you sir... I don't know ur name but thanks really

Answer 4

first of all you assign value 1 to i
when it entered in the loop compiler will check that the value of i is less than 6 or not.

if it is less tan 6 then the loop run.....and i will be multiply with i

but if it is equal to or greater than 6 then it exit the loop

means the loop runs again and again until the value of 6 is less than 6

Answer 5

I know the first iteration plz explain another iteration

Answer 6

I want step by step evaluation of this pgm I tried hard but getting difficult to find

Answer 7

hey in for loop did u write l+=2 or i+=2

Answer 8

yes it's i+=2

Answer 9

yep thats my ans also but it produce 19 as answer

Answer 10

if u excute this code it produce 19 As an answer