Array Manipulation

Question

Array Manipulation

This was the given question my code is attached

Write a function that for given two arrays (input arrays) returns a new array (output array) that contains elements of the input arrays that are divisible by 5.

Hints: Remember to pass sizes of input arrays into this function. Also, recall how arrays are returned from the function. More specifically, what is default mechanism for passing arrays into a funtion.

Example:
Input array #1:
1
15
23
10
20
79
80
55

Input array #2:
31
5
38
190
21
95
83
85
22

Output array:
15
10
20
80
55
5
190
95
85

Note: You do not need to return the size of the output array. You may assume that the size of the output array is always valid.

//i am not sure how to get the output array
https://code.sololearn.com/cOj4G6s6mr3Y/?ref=app

Answer 1

#include <iostream>
using namespace std;

int *generateDivisibles(int *arr1, int *arr2, int arr1Size, int arr2Size) {
static int divisblesArr[20] = {0}; //Supposing fixed size
int index = 0;
for(int i = 0; i < arr1Size; i++) {
if(arr1[i] % 5 == 0)
divisblesArr[index++] = arr1[i];
}

for(int i = 0; i < arr2Size; i++) {
if(arr2[i] % 5 == 0)
divisblesArr[index++] = arr2[i];
}
return divisblesArr;
}

int main() {
int arr1Size = 8, arr2Size = 9;
int arr1[arr1Size] =
{1,15,23,10,20,79,80,55 };
int arr2[arr2Size] = {31,5,38,190,21,95,83,85,22 };

int *divisblesArr = generateDivisibles(arr1, arr2, arr1Size, arr2Size);

for(int i = 0; i < 20; i++)
cout << divisblesArr[i] << " ";
return 0;
}

Answer 2

Updated to finish. Note I used globals as you called function twice instead of once with both inputs.
https://code.sololearn.com/ct3LtyPMmYN1