The output is 55, but I don't understand why the memory address of the *ptr is 23fe3c.

Question

#include <stdio.h>

int main() {
int a[5] = {22, 33, 44, 55, 66};
int *ptr = NULL;
ptr = a; /* point to the first array element */
ptr += 3;
printf("%d %x\n", *ptr, ptr); /* 55 */
}
/*The output is 55, but I don't understand why the memory address of the *ptr is 23fe3c.
Here's the output for different values of an increment:
(no increment) is 23fe30 (22)
ptr++ is 23fe34 (33)
ptr += 2 is 23fe38 (44)
ptr += 3 is 23fe3c (55) <--Where I confuse. Why "c"?
ptr += 4 is 23fe40 (66)
*/

Answer 1

How about 23fe40. How can it go from 23fe3c to that number.

Answer 2

How...