Uniform initialization

Question

Starting from C++11 one can use uniform initialization syntax with array new-expressions:
char* arr1 = new char[4]{'a','b','c' };
char* arr2 = new char[4]{ "abc" };
But how to initialize the string that is contained in the array (with uniform initialization syntax)?
char* arr3 = new char[4]{ arr1 }; //Error: a value of type "char*" cannot used to initialize an entity of type "char"

Answer 1

The problem here is that new cannot be used to assign arrays given as arguments. Arrays must be given directly to new with {} enclosing the content (Known as a brace-enclosed initializer list, used for direct initialization).

More details are given here:
https://stackoverflow.com/a/27663805

Even arr2's construction throws an error as the const char* literal acts as an argument rather than a brace-enclosed initializer list.