How to change length of mass?

Question

#include <iostream>
using namespace std;

int main()
{
int numbers[1];
numbers[0]=23;
numbers[1]=45;

cout << "before:" << endl;
for(int x=1;x>=0;x--)
{
cout << numbers[x] << "," << endl;
}
cout << "size = " << sizeof(numbers)/sizeof(numbers[0])<<endl;
//----------------
//try to cut mass and make it length 1
delete numbers[1];
//numbers[1]=NULL;
//----------------
cout << "after:" << endl;

for(int x=1;x>=0;x--)
{
cout << numbers[x] << "," << endl;
}
cout << "size = " << sizeof(numbers)/sizeof(numbers[0])<<endl;
return 0;
}

Answer 1

An array is a pointer for consecutive chunks of memory,
this means that if you try to delete one of the indexes of the array,
you are in effect trying to delete a chunk of memory.

Answer 2

Costa Jis,
If I understood, mass is in the array 'numbers' in index 1.
So to change it to 1 just do:

numbers[1] = 1;

Answer 3

I mean mass ‘numbers’ have length 2.
(numbers[0],numbers[1]).

How to change it length to 1? At result to have only numbers[0]? How to delete index [1]?

Answer 4

In my limited knowledge about C++ you cannot really delete index 1.
You just have to use only index 0 and if you will, add the a termination character ('\0')
to index.

Answer 5

How to write it? numbers[1]=‘\0’?
I can’t believe that in c++ we cannot delete object from memory

Answer 6

we can rewrite elements to a new chunk of memory as like as we want and then delete the old massive, is that operation correct?