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C++ task about mat and numbers
to create a program that imports 10 natural numbers from the keyboard and determines the product of the numbers in which the number one is encountered 3 times this is the task. #include <iostream> using namespace std; int main() { int p=1, n, r, k=0, s=1; for (int i=0; i<10; i++){ cin>>n; int b=n; while(b!=0){ r=b%10; if(r==1){ k++; } b=b/10; } if (k==3){ s=s*n; } } cout<<s; return 0; } and i don't know where is my mistake maybe in counting one number? Need help
12 ответов
+ 2
Okay Arsen try this:
#include <iostream>
using namespace std;
int main() {
int n, r;
long long s = 1;
for (int i = 0; i < 10; i++) {
cin >> n;
int b = n, k = 0;
while(b) {
r = b % 10;
if(r == 1) {
if(++k == 3) break;
}
b /= 10;
}
if (k == 3) {
s = s * n;
}
}
cout << "Product: " << s;
return 0;
}
+ 2
Arsen "while(b)" works the same way with "while(b != 0)" it checks whether <b> is non zero and continue the loop if it is. A mild difference be that "while(b)" doesn't compare <b> with zero, by skipping the comparison it works slightly faster.
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I'm not really understanding your intro, to prevent misunderstanding, some questions first;
Assume <n> = 3111 a number having 3 digit (1), then you want the product, but what number used to multiply with <n> to obtain the product?
What if <n> has more than 3 digit (1), does it meet the requirement? or it is necessarily 3 digit (1)?
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They multiply by what? for example <n> = 3111 then multiply <n> with itself (squared) or <n> * 3 (number of digit (1)?
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Give me one example please, I still don't understand what to multiply the number with, I'm confused XD
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Okay now I understand what you want : )
Let me see that code again and I'll get back to you later ...
+ 1
Ok ipang but why you write w
while (b)
What does it mean
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Only 3 digits of 1 number not more and not less
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And if my numbers have 3 digits 1 number they multiply
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No I am going to import 10 natural numbers chek if my numbers have 3 digits of 1 number they are going to multiply
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For example I have 3245 3411 2311 3111 121 111 234 890 765 340. This are my 10 natural numbers. If they have 3 digits of the number 1 they multiply. In my example this numbers are 3111 and 111 and answer is 3111*111
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Ok