C++ task about factorial

Question

Complies a program that imports N natural number and outputs YES if this number is a factorial number and NO otherwise
I have a question
Can anybody solve this task without arrays recursion and function

#include <iostream>
using namespace std;

int main() {
int number, temp;
cin>>number;

if(number<=0){
cout<<"error";
return 0;
}
int counter=1, sum=0;
temp=number;
while (counter<temp){
if(temp%counter==0){
sum*=counter;
counter++;}
else{
cout<<"no";
}
}

if (number==sum)
cout<<"yes";

return 0;
}

I don't know I am in a right way

Answer 1

1. Initial value of "sum" shouldn't be 0 as sum*=counter wouldn't have any effect on it. Try sum=1.

2. You can simplify your program by changing the while loop to:

while (number%counter==0){
sum*=counter;
counter++;}

Answer 2

Can you please paste your code in the Playground and share the link? It'd make it easier for people to help you.

Answer 3

Here you go:
https://code.sololearn.com/co3W3l7SEZ0H/#cpp

Answer 4

As Diego said, also use code feature that you got here on SoloLearn so it will be easier to solve your problem

Answer 5

Diego I try with sum=1
And changed the loop but it doesn't work

Answer 6

https://code.sololearn.com/c6Z7D13gDwmr/?ref=app

Answer 7

Sorry for so much late I answered your question but in my country was night so I went to sleep

Answer 8

Zen thanks for helping me
It works