Else statement not running

Question

Does anyone know how to fix an error that happens when the input is a string? I want that input to trigger the else statement! Thanks!
https://code.sololearn.com/c6819kF6kQuY/?ref=app

Answer 1

Because when you are getting the input with nextInt the compiler always expect a number, and as such if you give a string an error will occur. I suggest you get the number as string then convert it to integer to compare it with the 18.

Answer 2

use this to check for integer input

if(KeyBd. hasNextInt() ) {
input = KeyBd. nextInt() ;
} else {
System.out.println("your message" ) ;
}

Answer 3

You are storing the variable as int, so you can't store in it string.

Answer 4

Int input = ...nextInt() --> you have to input a number.
String input = ...nextLine () --> input a String

But in your case I would use try/catch.

int input = 0;

try {
input = keyBd.nextInt ();
} catch (Exception e){
System.out.println ("I'm sorry, I did not unterstand that!")
System.exit (0);
}

The Scanner expects an int number, if not you would get an error. But the code will catch this error (outprint: I did unterstand...) and exit the program.

Edit: https://www.sololearn.com/learn/Java/2175/

Answer 5

Yogesh But your program don't solve the problem if the input is String.

Answer 6

Норм

Answer 7

Норм делаем программу