I need a little help with this code. Whoever can complete it and find an answer for a,b, and c will get all their codes upvoted

Answer 1

a =3
b = 15
c=0
but the value of c depends on compiler. some compilers return a random value from ram but others use 0 as a initialization.

Answer 2

#include <iostream>
using namespace std;

int main()
{
int a = 0;
int b = 0;
int c;
while(a<3){
b = b+5;
a++;}
return 0;
}

Answer 3

I see. I didn't know that. how did you get b=15? I know that when you run the code that is what comes up. But is there a way to break it down? and does the a++ have any effect on a's value?

Answer 4

b = b +5 means add 5 to b .
a ++ means add one to a .
a++ equals to a= a+1.

Answer 5

when execution enters while loop
it checks the condition, (here a<3)

1st iteration -
a=0, condition satisfied
so b = b+5 and a++ (a = a+1) are executed
now b=5 and a=1
now execution goes back to the condition

2nd iteration -
a=1, condition satisfied
so b = b+5 and a++ (a = a+1) are executed
now b=10 and a=2
now execution goes back to the condition

3rd iteration -
a=2, condition satisfied
so b = b+5 and a++ (a = a+1) are executed
now b=15 and a=3
now execution goes back to the condition

4th iteration -
a=3, condition not satisfied
so its skips all the while loop statements to return 0 statement.

Answer 6

wow.. well, this kind of explanation should be part of the training here. you just broke it down barnie style. thanks a bunch! @mojtaba @akash. up votes coming right up!

Answer 7

if I follow that, wouldn't a= 4 and b= 5? this is the part that gets me