Can anyone help me??

Question

read this program---

def oct2(n):
print("passed octal no.:",n)
n=str(n)
decNum=int(n,8)
print("Number in Decimal:",decNum)
print("Number in Hexadecimal:", hex(decNum))
print("Number in Binary:", bin(decNum))
num=int(input("Enter an octal number:"))
oct2(num)

Here, what is the use of
decNum=int(n,8)
I can't understand.
Can anyone help me??

Answer 1

There are 4 main systems of representing numbers:

- Decimal numbers (base 10)
- Hexadecimal numbers (base 16)
- Binary numbers (base 2)
- Octal numbers (base 8)

In Python, the `int()` function is defined as:

def int(str, base=10):
# ...

It receives a string value and an optional base, which defaults to 10.

Basically, all it does is it converts a string into a number. The number is formatted with the base as its rule.

int("10", 8)

Will output 8 because it is base 8 (or an Octal value)

Answer 2

It is a pleasure 😊

Answer 3

Diego ooh sorry, did quick math 😶🙂

Answer 4

Thank you Gordon and Edwin Pratt. Thank u soo much.

Answer 5

Treating the string as a number under octal number system (base 8), and converts into int of decimal system (base 10)
https://code.sololearn.com/cTB38H7UyEfD/?ref=app

Answer 6

Edwin Pratt int("10", 8) will output 8, not 13.