Why this code is printing 0 and 1?

Question

https://code.sololearn.com/c51IJrxzZTR5/?ref=app

Answer 1

@Honfu that is true.

Made some example code to show, what is happening
https://code.sololearn.com/cICtb50w1si1
https://en.cppreference.com/w/c/language/operator_precedence

Answer 2

Hm, maybe 1<<-1 is not possible and returns 0, like other operations (type conversions) sometimes do?

Excited to hear the solution!

EDIT:

Ha, no, minus seems to just change the direction of shifting. So 1 << -1 seems to work like 1>>1 which is 0.

Answer 3

Werg Serium thanks bro
Now I understand

Answer 4

sneeze thanks bro now I understand your code

Answer 5

printf("%d\t",1<<2);// 0001 shift two to left 0410 (decimal 4)
Why this line is printing 4??

Answer 6

sneeze Sorry bro I didn't Understand.

Is "<<" this is conditional operator?

Answer 7

I learn something new everyday. Thanks sneeze for that lesson about left/right shift by negative values.

Answer 8

sneeze I didn't understand😭 bro

Answer 9

Conditional operator
< smaller than
> Greater than

Mathenatical operator
<< Shift left
>> Shift right

Answer 10

<< is not a conditional operator. Did you want to compare ?
Please elaborate more what do you want to achieve ?

Answer 11

That's because first occurs 2-3, and after it will do 1<<-1 this is why first print 0

Answer 12

If you use parentesis it will occurs first 1<<2 and after will do 4-3 like you did in the second print.

Answer 13

Remember 1<<something is doing 1*2^something.

Answer 14

Ok. Excuses

printf("%d\t",1<<2);// 0001 shift two to left 0410 (decimal 4)

was a typo error should be

printf("%d\t",1<<2);// 0001 shift two to left 0100 (decimal 4)

I have corrected it in my code now