cout << printf; // output: 1

Question

Why do I get a 1 as output if I cout a function name?

Answer 1

~ swim ~ If printf returns the no of chars then can we write like this

int charsCount = printf("Hello");
OR
char arr[] = "Hello";
int charsCount = printf("%s", arr);

Which piece of code is valid or invalid?

Answer 2

Alright, thank you for answering :)

Answer 3

How about:

int arr[printf("Weird sizing")];

That gonna work? 😁

So basically if I cout a function name I get the answer: "Yep, this function does exist."

Thanks, ~ swim ~!

Answer 4

~ swim ~ i thought the return value of printf function is 1

Answer 5

Yeah, Jay, that's the usual return value.

I knew about that before; I didn't know you can bool a function though.

Answer 6

~ swim ~ I think you meant nAutAxH AhmAd and not *AsterisK* in one of your comments above. They both have darkish avatars and nearly fooled me too.

Answer 7

When you write any function name without the parentheses it gives you the address of that function, since printf exists the adress is more than 0 which returns true.