Why do I get 0True as the answer instead of just True when I type the following code?

Question

x = input ( int())
print ( 2 != "x")

>>>0True (if the required input number is 2)

Answer 1

It's int(input()), not input(int()). input() will print what is inside the parentheses and int() is 0

Answer 2

hi anushree sabnis,
you get the 0 from the int() method.
try this
x = input ()
print(x)
print ( 2 != "x")

if you want to check the input is an int value, try this
user_input = input ("Enter a number")
try:
val = int(user_input)
print("Yes input is an Integer.")
print("Input number value is: ", val)
if(val != 2):
print("User number is <> 2 ")
else:
print("User number is == 2 ")
except ValueError:
print("That's not an int!")
print("No.. input is not an Integer. It's a string")