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How do I understand this kind of output?
import re pattern = r"[aeiou]" hello = re.search(pattern, "grey") print(hello.group) >>> <built-in method group of re.Match object at 0x02F2C6B0>
8 ответов
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group() is a method of the.Match, so you should be calling it as a method and not printing the function itself.
print(hello.group(0))
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hello = re.findall(pattern, "grey")
print(hello)
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In addition: You should never use group() alone because it will raise an exception if the pattern doesn't match the string
if hello: # there is a match
print(hello.group(0))
else:
pass # no match => no group(0)
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Hatsy Rei but if if i did anyway, what does the output means
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i tried indexing and it worked. thanks
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Anna this one works too.
means i'll have to use braces
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it returns the first letter matched.
what if i need a list of all letters matched
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thanks, i now should not forget earlier lessons