Printing the lines that contain the substring 'snake'

Question

#opening the text file

f= open("Acrochordidae.txt", "r")

for data in f:

    lines= f.readlines()

    if lines == "snake":

        newline= f.readline()

    else:

        break

print(newline)

I tried to format it in different ways but this is how far I got.

Answer 1

lines = open('yourfile.txt', 'r').readlines()
matches = [line for line in lines if line.lower().find('snake') != -1]
print(matches)

Answer 2

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Answer 3

for data in f will give you the lines in f, no need to use lines= f.readlines(), especially not in the for loop

if lines == "snake" will check if the whole line equals "snake", not if "snake" is somewhere in the line (use if substring in string)

newline= f.readline() doesn't make sense

else: break will break the whole for loop as soon as "snake" is not in a line

Answer 4

So you want to
1.Open a file
2.Print out lines that contain "snake" right

Answer 5

And I'm sorry if my code didn't make sense. I'm still trying to understand file handling. I will try to get better.

Answer 6

yes

Answer 7

I just need understanding how to format it right. Like finding the substring.

Answer 8

Thank you. I will try if it works.