How is the output 84

Question

Int x = 7, y=4;
If(++x > 6 || ++ y <5)
Cout<<x<<y;
else
Cout<<x*y;

Answer 1

x = 7
So the evaluation for `++x > 6` yields true, and simultaneously increased value of <x> to become 8. Logical OR operator returns and yet doesn't check successive operands when the first one evaluates to true, that's why `++y < 5` is not getting executed (value of <y> remains to be 4).

Because `++x > 6` evaluates to true, the `if` statement executed the `if` block rather than the `else` block.

Hth, cmiiw

Answer 2

This is called short circuiting, where successive operands are not checked when the result of the OR is already true.

Answer 3

You're welcome 👍

Answer 4

Thanks

Answer 5

++x = 8 ++y = 5 answer 84 (concat output) 🤔