Why my code not run when i put -1 or 4+? what is the wrong? anyone help me?

Question

<?php
//LIFT of my 4 storyed Building... :)
$select_the_floor=0;

switch ($select_the_floor) {
case '1':
echo "welcome to Level 1";
break;
case '2':
echo "welcome to level 2";
break;

case '3':
echo "welcome to level 3";
break;

case '4':
echo "welcome to level 4";
break;

if ($select_the_floor<1) {
echo "Ground floor is not available right now and ";
}
elseif ($select_the_floor>4) {
echo "This is 4 storyed Building and More level is coming soon";
}

}

?>

Answer 1

You're welcome, I'm glad if it helps my friend 👍

Answer 2

You can't do if statements inside a switch statement.

I would rework your code to be:
if ( < 1) {
Thing
} elseif ( > 4) {
Other thing
} else {
switch() {
More things
}
}

Answer 3

You are placing the `if..else if` block outside any valid case. You can actually use `if..else` block inside any of the case (even inside the `default` case), just make sure they go before the `break` statement.

Here I revised your code, moved the `if..else` block into the `default` case.

<?php
$select_the_floor = 5;
switch ( $select_the_floor )
{
case 1: case 2: case 3: case 4:
echo "Welcome to Level $select_the_floor";
break;

default:
if ($select_the_floor < 1)
{
echo "Ground floor is not available right now.";
}
elseif ($select_the_floor > 4)
{
echo "This is 4 storyed Building and More level is coming soon.";
}
break;
}
?>

Hth, cmiiw

Answer 4

Code is unreachable, due placing it after the break; statememt in your switch block. Insert a default: to handle any other case.

Answer 5

Ipang thank you Sir, you solved the problem easily...