What is the output of this code? $x=2; $y=++$x; echo $x+$y;

Question

Why the answer is 6

Answer 1

Garuda first only value of x is changing due to pre increment and due to assignment of value of x in y. y value to be changed by 3 so both value become 3

Answer 2

Garuda hi,
$x = 2;
$y = ++$x;
So $y = 3
$x = 3 due to pre increment the value of x is change to 3 and this 3 is assigned to $y that's what 3+3=6
6 come as output

Answer 3

If we used $y=$x++; the answer would be 5.

Answer 4

So the true answer 5 or 6?

Answer 5

but in my opinion the correct answer is 5, because x=2 and y=x++ so x+y=2+3

Answer 6

Garuda according to your questions in which pre increment the answer will be 6 and according to Sonic comment for using post increment then value become 5

Answer 7

Value y=3?
And so the value of x changes to 3 too?

Answer 8

thank you for your answer DishaAhuja

Answer 9

Answer 6

Answer 10

salom

Answer 11

Answer 5