Whats wrong with this code can anybody tell?

Question

#include <stdio.h>

int main()
{
int age=40;

switch {
age
'15'=printf("to young"),//case1
'40'=printf("adult"),//case2
'70'=printf("old")//case3
}
return 0;
}

Answer 1

0. You aren't checking the age in the switch statement.
1. You have no cases.
2. The numbers shouldn't be enclosed in single quotes.
3. You need a colon after each case.
4. You need a break statement after each case (or you'll fall through to the next statement)
5. (Optional) You can add a default condition to handle values you are not checking for.

Change it to:

#include <stdio.h>

int main(void)
{
int age = 40;

switch (age) {
case 15:
printf("too young\n");
break;
case 40:
printf("adult\n");
break;
case 70:
printf("old\n");
break;
default:
printf("Unexpected age.\n");
break;
}

return 0;
}

And it'll work as expected.

Answer 2

switch(age)
{
case 15:printf("too young");
break;
case 40:printf("adult");
break;
case 70:printf("old");
break;
}

Answer 3

Cluck'n'Coder thanks bro for explaining.

Answer 4

https://www.sololearn.com/learn/CPlusPlus/1618/

Answer 5

#include<stdio.h>
int main(void)
{
int age=40;
Switch (age>0)/* if we declare age>0 it will good in practical way*/
{
case 15:printf("too young\n");
break;
case 40:printf("adult\n");
break;
case 70:printf("old\n");
break;
}
return 0;
}