Java code

Question

How this code runs?
isn't like this way?

4
2
3
remove(2)
4
3
Collections.sort(ListName)
3
4
System.out.println(ListName.get(0)*ListName.size());
3*2
output:6

https://code.sololearn.com/c1A112xSHWIT/?ref=app

Answer 1

In simple words
Remove 2 means remove index 2
Explantion
ArrayList <Integer> list = new ArrayList <Integer>();
list.add(4); // index 0
list.add(2);// index 1
list.add(3);// index 2
list.remove(2);// remove 3 after this line list size will be 2;
Collections.sort(list);// 2,4 after this line in index 0 replace with 2 and Index 1 replace with 4
System.out.print(list.get(0)*list.size());// 2 * 2 = 4;

Answer 2

remove(2)
argument 2 is actually index of your arraylist.

4 (has index 0)
2 (has index 1)
3 (has index 2)

So, you are removing 3,
then you sort it (2,4)
and then you multiply 2 with size of your arraylist which is 2.
And your output is 2*2=4.

If you want 6 to be your output, then remove element with index 1.
remove(1)

Answer 3

Oh i thoughts removing elements 2... careless mistake