How does strcpy() works in the code below. Why no Runtime Error ?

Question

Can anyone explain how the following C code works ?
Correct Answer : E

Question :

#include<stdio.h>
#include <string.h>
void main()
{
char string[14] = "i love coding";

char * pointer = string ;
pointer += 7 ;

strcpy(pointer,"programming");

printf("%s",string);
}

Options :
A) i love
B) i love coding
C) Compilation Error
D) programming
E) i love programming
F) Runtime Error

Answer 1

pointer - - > first index
pointer+=2 - - > 2nd index
pointer +=7 - - > 7th index (this is saying start from the 7th index)

strcpy(pointer,"programming"); the strcpy just copy the string to the contiguous memory which has been allocated and go beyond if need be, because it was not instructed not to

Answer 2

Strcpy does not give warning or runtime error in C. Due to unchecked memory access in C the strcpy has no info about pointer that you have declared as in from which memory address location. It's better to use strncpy instead to avoid overlaps