What is the problem with this code

Question

for n in range(2,10):
for x in range(2,n):
if n%x ==0:
print(n,'equal to',x,'*',n//x)
break
else:
print(n,'is a prime number')
It print too many prime number.
When i add break in the last line, the code execute in the first codition and also return 9 is a prime number , which isn't.

Answer 1

Add a little extra debug:

# last line
print(n,'is a prime number ( x:',x,')')

3 is a prime number ( x: 2 )
4 equal to 2 * 2
5 is a prime number ( x: 2 )
5 is a prime number ( x: 3 )
5 is a prime number ( x: 4 )
6 equal to 2 * 3
7 is a prime number ( x: 2 )
7 is a prime number ( x: 3 )
7 is a prime number ( x: 4 )
7 is a prime number ( x: 5 )
7 is a prime number ( x: 6 )
8 equal to 2 * 4
9 is a prime number ( x: 2 ) # but...you haven't run all the tests yet
9 equal to 3 * 3

Answer 2

add a check for each prim which would try to divide the number in a whole but since it's a prime number it can't so it would be put in a boolean witch would count it as true

Answer 3

Okay. But i still feel a little bit extra. How can i cut down these multiple line