Char comparison

Question

I came across with this
/////////////////////////////////
int main (){
char x [] = "bye" , y[] = "bye";
if (x!=y)
cout<<"not"
cout<<"equal";

return 0;
}
////////////////////////
Output
notequal

Why is the if conditional true? Is it because "x" and "y" are pointers which hold different addresses?

Answer 1

You are correct. Add an asterisk to both x and y to compare the first characters of both strings.

Answer 2

Thanks!

Answer 3

To compare following chars in a string and if they're equal, raise the counter. With my example code I always get TypErrors related to line 6. Do you know where's the problem?

def func(text): counter = 0 text_l = text.lower() for i in text_l: if text_l[i+1] == text_l[i]: print(text_l[i+1], text_l[i]) counter += 1 return counter

Answer 4

@PoloLadyCoder - You are checking the current character with the next character, but what happens when you reach the last character of the string? -> You end up checking past the string length.

Changing your for-loop condition to:
for i in range(len(text_l)-1):

- should solve the problem. If not, let me know.