Why does the following code outputs 22:

Question

#include <iostream>
using namespace std;

int main()
{
int x=3;
if(x=2){
cout << 2;
}
else {
cout << 3;
}
cout << x;

return 0;
}

Answer 1

My best guess is:
because it is x = 2, it assigns x to 2, then it is automatically true therefore outputting a 2 as you told it;
cout << 2;

when the program exits the if statement, x is set to 2, so it prints 2, resulting in 22.
If you added an endl; it would be 2 2.

Answer 2

@ルカ he is asking why it outputs 22, not why it is'nt working, which in this case, there is no errors