Character Array in C

Question

Can any one tell me what is wrong in this program ?
//********************************************************************
#include<stdio.h>
int main()
{
char a[5]={' ',' ',' ',' ',' '},search;
for(int i=0;i<=4;i++)
{
printf("\n Character %d:",i+1);
scanf("%c",&a[i]);
}
printf("Enter character to be found");
scanf("%c",&search);
for(int i=0;i<=4;i++)
{
if(a[i]==search)
{
printf("\n\n\t%c is found at %d",search,i+1);
break;
}
if(i==4)
{
printf("\n\n\t%c is not found",search);
}
}
return 0;
}

Answer 1

you need to enter the input on a separate line and your condition to check if its not found should rather be if(i>4) since you have an index 4 in the array
put a space in the scanf like this scanf(" %c",); for both scanf

Answer 2

yash nigam what is your expectation? I just gave input as below :

a
s
d
f
g
s

and it worked