Can anyone explain the behavior of the code snippet?

Question

#include <stdio.h>

int main() {
int a[] = {1, 2};
char *p;
p = (char*)a;
printf ("%d\n",*p);
p = p + 1;
printf ("%d",*p);
return 0;
}

Answer 1

int require 4 bytes so a is 8 bytes in size. char requires 1 byte so you print 2 bytes of a. Change p to: int *p; and you would get both integers.

Answer 2

Thanks John Wells.

Answer 3

John Wells can you please explain me about the code working