How to obtain this pattern as a output in python

Question

I
*
***
*****
*******
*********

Answer 1

n = int(input())
n = 3 if n < 3 else n
for i in range(n):
sp = ' '*(n-i)
print(sp + '*'*(2*i+1)+sp)

Answer 2

Use loops - for / while.
1 loop to print row elements.
2 loop to print columns.
1st loop inside the 2nd loop.