Not Working

Question

#include<stdio.h>
void too (int &y){
printf("y = %d\n",y);
y=6;
printf("y =%d\n",y);
}
int main()
{
int x=5;
printf("x = %d\n",x);
too(x);
printf("x = %d\n",x);
return 0;
}

Answer 1

#include<stdio.h>

void too (int *y) // need a pointer here
{
printf("y = %d\n", *y);
// print value by dereferencing pointer
*y=6;
// change pointer value
printf("y = %d\n", *y);
// print value by dereferencing pointer
}

int main()
{
int x = 5;
printf("x = %d\n", x);
too(&x);
// pass the <x> variable address
printf("x = %d\n", x);
return 0;
}

This works, please see inline comments 👆

Answer 2

I think u has to procide y as argument not &y

Answer 3

Jordan then u must use return y in toofunction

Answer 4

Variable references don't work in C, you must use a pointers.

Answer 5

its answer should be
5
5
6
6

Answer 6

By writing y
O/p: 5 5 6 5
but correct answer is i mentioned above.