Im trying to make something... Help?

Question

I'm trying to make a code that will solve for a Mathematical reference angle in python. I dont know how to make the code subtract from user input to solve for the reference angle. Help?

Answer 1

Well I want the user to input an angle say 150 (which is 30 away from the x axis) and make it subtract and set as new value. Should I set user input as a variable like:

input ("Enter an angle.")

input == x

Then just subtract like:

x -= 180

x ** 2

x // 2 (I think that's root.)

>>>
30
>>>

The reason I put the square and then root is to get rid of any negatives just in case it is. I could of also done:

If x < 0:
x *= -1
else:
x += 0

Thoughts?

Answer 2

I guess I'm talking for most people here if i say: What angle are you talking about?

Answer 3

A reference angle is just an angle between the terminal side and the x axis. But the thing I'm asking about is how to subtract from the user input say if it's greater than 180, to subtract and set new value. If I need to teach a lesson on reference angles I can but I don't need someone to make the whole code for me, just what I specified.

Answer 4

You probably talking about angle functions like sin cos and tan
And why the subtraction, a simple if statement should do the trick to set the imput to 180.

Answer 5

I still don't see a problem(and there is no need for else)

Answer 6

True, but it says invalid syntax when I do x -= 180
^

Answer 7

Same problem with x = x - 180?

Answer 8

I'll try that.

Answer 9

How should I set input to equal a variable like x? It says it's not defined.

Answer 10

Define it with x = 0

Answer 11

Now it's saying there is a problem with:

if x > 180
^

Answer 12

With or without the :

Answer 13

With

Answer 14

OK send the whole statement

Answer 15

#terminal angle aka Reference angle...

#solver

input ("Enter an angle!")
x = 0
x = input

if x >= 180:
x = x - 180
else:
print("Working...")

print ("This is your Reference Angle: " + x)

Answer 16

Kinda the same trick if x > 179:

Answer 17

I'll work on this later, if you want to help, see what you can do. Goodnight!