If else question

Question

X=True
Y=False
Z=False
if X or Y and Z:
print ('yes')
else:
print ('no')

Isn't this expression supposed to print 'no'?

Answer 1

Becuase x is true the rest of the exspression is ignored and prints yes

Answer 2

I think and has a higher priority than or so Y and Z evaluates first resulting in False then X or false results in True.

Answer 3

You got indentation error for print

Code: -

If X or Y and Z=='False':
print('yes')
Else:
print('no')

Answer 4

'or' operator means any of the one if is True then will print 'yes'.

Answer 5

Ok thanks

Answer 6

It prints yes because and has higher precedence order than or.

You can use parentheses to control operation precedences.

Answer 7

priority order is NOT AND OR
use this
Y AND Z = FALSE
THEN
X OR FALSE = TRUE SO answer is TRUE

Answer 8

Priority order- NOT>AND> OR
Therefore;
If X OR Y AND Z = IF X OR (Y AND Z)
So you will solve brackets first.
This implies, Y AND Z= FALSE AND FALSE
= FALSE
NOW X OR FALSE = TRUE OR FALSE
= TRUE
THUS , this code will print 'yes'.

Answer 9

Yes because you used 'or' statement so one condition is required to be true.

If X 'or' y and z

For detail these is Logical operators
Or
And
Not