How can i make a range of alphabetical letters in python by range function

Question

Like range(a,z) won't work , i want a similar and valid code like that . Anyone having any tips?

Answer 1

Very simple, you can create with just one line:
Two simple ways:
Alphabetlist = [chr(i) for i in range(97, 123)]

Or if you would rather print them directly without saving them in a list:

print(*(chr(i) for i in range(97, 123)))

Answer 2

Try using the chr - function. It turns an int into a letter.

You can look that up in the ASCII table.

Hint: chr(97) will give you 'a'

Answer 3

That IS very easy!

Try it out:

print(chr(97))

Answer 4

https://code.sololearn.com/c7BKfiYRGGwn/?ref=app

Answer 5

look up the string module too, it has a method to get alphabetical character i .e lowercase, upper or both as a string so you can sent it to - for example- the list constructor.
By 'range' i assume you mean ' a collection' rather than python range function.
import string
mystring1 = list(string.ascii_lowercase)
print(mystring1)
# or... depending on wht you want
mystring2 = string.ascii_lowercase
print(mystring2)

Answer 6

Yo thanks a tonne fellas.
It was really helpful!!👌😊