How to count the number of digits of a number?

Question

Just like length() but only for integers

Answer 1

If you want to use length() method then you can first convert the number to string and then use length()

e.g. int a = 13445;
String s = String.valueOf(a);
int l = s.length();

Answer 2

Miguel Ángel Your method appears to return a count of 0 for the value 0, which has 1 digit.

Answer 3

Static int countDigit(long n)

    {

        int count = 0;

        while (n != 0) {

            n = n / 10;

            ++count;

        }

        return count;

    }
Then in the main you call the method and pass the number by parameters.

Answer 4

Rishi Anand
You can shorten it:
int number = 1234;
int length = Integer.toString(number).length();
//or String.valueOf(number).length();

Miguel Ángel
Another problem: negative numbers

Btw: if you use the string version it counts also the minus sign.
123 => length = 3
-123 => length = 4

Answer 5

Hatsy Rei true, it's better then that in while, the condition have the length of the parameters i think.
Good job.