Adding one to the multiplying or exponenting etc.

Question

I want phyton to add 1 by itself to my multiplying
(sorry, can't describe my problem)
let's say x = 2
x **= 2 should output 4 as 2^2 is 4
i want it to make it x **= 3 by itself
if possible can it stop in a point, for example 28( x **= 28
and how could i add them together like

x = 2
print(x **= 2 + x **= 3 + x** = 4)
Basically this is what i want my code to do for me. Any help is valued, thank you for your time

Answer 1

x = 2;
y = 2;
sum = 0;

while y <= 28 :
x **= y++
sum += x
print(sum)

# Not the best at python
# But yeah lol
# I might have made errors on the syntax tho
# Take note that value of x changes each loop
# Not sure if you want that to happen
# If you don't, just replace x with 2.

Answer 2

I cross-checked things on Code Playground and found out that some of the syntax may not have been compatible with Python. (I main C++)
I've made another version of the code, please try if it works.

x = 2;
y = 2;
sum = 0;

while y <= 28 :
sum += (x ** y)
y += 1
print(sum)

I realise that I'm doing semicolons in variable declarations. This is a C++ thing and is totally unneeded in Python. I just... feel comfortable doing it and apparently it doesn't cause an error lol.

Answer 3

@Magnum Opus

print("Your result is " + str(sum))

Answer 4

The error might be due to the resulting value exceeding integer upper limit. Sum is just a variable, while is a type of loop. You may refer to the Python Tutorial here on SoloLearn.

Answer 5

I wrote it down exactly as you said, only changed 28 with 64, it gave some syntax error at first but now it doesn't, but it doesn't print any result neither :( where can i learn sum and while and why did you use ; and : in some lines, thank you

Answer 6

This one works! Im going to school now, how do we add a name to it like
Your result is 536870908