What will be the programme of ( ax2+bx+c-d=0)

Answer 1

a*x*Math.pow(2)+b*x+c-d=0

Answer 2

ax² + bx + c = 0 would be solved by:
double x[ ] = {(-b - Math.sqrt(b*b - 4*a*c)) / (2 * a),
(-b + Math.sqrt(b*b - 4*a*c)) / (2 * a)};