Why the output is “hi” not “bye”?

Question

def say(*args)
args[0].call
end

def something
if block_given?
return yield
end
lambda{p "hi."}
end

say something do lambda{p "bye."}
end

Answer 1

if you want to output "bye" then "hi":

def say(*args)
args[0].call
end

def something
if block_given?
yield
end
lambda{p "hi."}
end

say something {p "bye."}

Answer 2

Because the interpreter thinks that you are providing block to the say method, not something. Parentheses it is not always a bad idea :)