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HELP WITH EASY HOMEWORK CODE - [Dynamic Memory Allocation]
Hello, I am taking C++ beginner class and I can't get to do this. The instruction is: 1. cin >> size of array 2. cin >> number (in array) 3. cout << "Number of values grater than the average is " << ( HINT : int* list = new list[size] ) And the answer should be this. Enter array size: 3 Enter number: 1 Enter number: 5 Enter number: 7 The number of values greater than the average is 2 Please, some help :(( I don't know how to get the average or how to make the "enter a number" repeat when using dynamic memory allocation.
4 ответов
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Ok, thank you very much for your help - swim - !
I will keep working on that!
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I'm sorry, I know what you mean. Here I tried to do this code:
#include <iostream>
using namespace std;
void aboveAvg();
int main()
{
int size, i;
double sum = 0;
double Avg;
cout << "Enter array number: ";
cin >> size;
int* list = new int[size];
for (i = 0; i < size; ++i)
{
cout << i + 1 << "Enter a number: ";
cin >> list[i];
sum += list[i];
}
Avg = sum / size;
cout << "The numbers greater than average are: " << aboveAvg() << endl;
return 0;
}
void aboveAvg(double Avg, int *list){
if (*list > Avg)
{
cout << *list << " " << endl;
}
}
------
I only have one error which says " no operator << matches this operands" before aboveAvg << endl;
I need some guidance with that. Also, if someone could check if my void code is correct I would really appreciate it, I still find it difficult to understand how to call array and its elements into a void function.