How to find lowest number in Array

Question

Can anyone help me please?
I have to access multiple arrays looking like this:
[B8,2,B6,4,C5,7,E5,7,F8,3,G4,1],
[A2,3,B5,1,C6,3,A5,4]
The length of arrays is different, but it always starts with a string of 1 letter and 1 number (i.e. A1) followed by a number between 1 and 8.
The content of Arrays differs from 1 pair to maximal 8 pairs.

Maybe there is some kind of dictionary-object better suited for this problem, but I didn't find satisfying solutions on the web so far...

I want to get the indexOf() entry before lowest number, in my examples that would be indexOf(G4) - 10 for the 1st array and indexOf(B5) - 2 for the 2nd.

Is there an easy way to do that or do I have to iterate over complete array every time?

Answer 1

Iterate only once to create a dict and use build-in function 'min()':

def arr2dict(arr):
dic={}
for i in range (0,len(arr),2):
dic[arr[i]]=arr[i+1]
return dic

arr1=['B8',2,'B6',4,'C5',7,'E5',7,'F8',3,'G4',1]
arr2=['A2',3,'B5',1,'C6',3,'A5',4]
print(arr1)
print(arr2)
dic1=arr2dict(arr1)
dic2=arr2dict(arr2)
print(dic1)
print(dic2)
m1=min(dic1, key=dic1.get)
m2=min(dic2, key=dic2.get)
print(m1)
print(m2)
print(arr1.index(m1))
print(arr2.index(m2))

Answer 2

thank you very much