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If I don't want to use namespace and use <cstdlib> for std :: cout, it gives an error "string does not name type".
Should I add any other library? https://code.sololearn.com/c01RH8Khw74C/?ref=app
6 ответов
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Master Forts
This way you can do so change string to
std::string variable_name;
std::endl;
https://code.sololearn.com/cLNAxGo65i33/?ref=app
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Alright, Thanks for elaborating, now I understand this better.
Well, for one thing, I can assure you that you may not need to include <cstdlib> just because you don't use "using namespace std;". You only need <cstdlib> if your code uses one of the functions, constants etc. that is defined in <cstdlib>.
For everything defined in standard namespace (std), you will have to write the syntax in full form. That means you prefix the syntax with 'std::' such as (but not limited to):
std::cin instead of just cin
std::cout instead of just cout
std::endl instead of just endl
std::string instead of just string
Or alternatively, as you have learned ...
using std::cin;
using std::cout;
using std::endl;
using std::string;
Less hassle this way ...
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Thanks for your interest. I want that same code without using namespace std; In C ++ the namespace is seen as bad programming because finding an error would be difficult. So if I remove it in the code, I must add the <cstdlib> library and declare: using std :: cout; using std :: cin; using std :: endl; But in doing so, having a copy constructor, on line 13, the word string fails when I declare the copy of the data constant. For that same code to work without namespace, what modifications should I make?
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brilliant thank you very much
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Very grateful, timely explanation as I try to understand that syntax.

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Can you please edit your question? I am not understanding your question. The code runs with no problem, BTW.