The Spy Life

Question

Task:
Create a program that will take the encoded message, flip it around, remove any characters that are not a letter or a space, and output the hidden message.

msg = input("")
alphabet = list("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")
def remove(x):
for item in x:
if item not in alphabet: x = x.replace(item, "")
return x
print remove(msg[::-1])

Why doesnt my code work? Thanks

Edit: Solved.

msg = input("")
alphabet = list("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ ")
def func(x):
for char in x:
if char not in alphabet: x = x.replace(char, "")
return x
print (func(msg[::-1]))

Answer 1

1. You forgot about the space, add a space to the end of your list.

2. return should be outside the loop, not inside.

3. print should have parenthesis: print(remove(msg[::-1]))

Answer 2

You can use regular expressions to match any non-string. And [::-1] to flip any string. For example

import re
inp = input()
print(''.join(re.findall(r'[a-zA-Z]|\s', inp[::-1])))

"re.findall(r'[a-zA-Z]|\s', inp[::-1]" this returns a list of everything that matches a word (a-z or A-Z) in inp[::-1] which is the reverse of the string

Answer 3

here is my solution. hope it helps.

import re

text = input("")
text = re.sub("[^a-z A-Z]+", "",text)
print(str(text[::-1]))

Answer 4

The second testcase is not being passed
My output:youaregreat
Expected output:you are great
This is my code
string=input()
list1=[]
i=0
length=len(string)
while(i<length):
for letter in range(97,123):
if(string[i]==chr(letter)):
temp=list1.append(chr(letter))
else:
letter+=1
i+=1
str=""
str1=str.join(list1[::-1])
print(str1)

Answer 5

Akshaya Arunkumar put a space in the alphabet list

Answer 6

import re
x=input()
y=re.findall(r"[a-zA-Z\s]",x)
print("".join(reversed(y)))