Repeat the Die Roll n times and suggest which number between 1 and 6 fall maximum number of times.

Question

I don't understand where I am going.
Please help!

Below is my code:

import random
f1=0
f2=0
f3=0
f4=0
f5=0
f6=0
n=int(input())
for i in range(0,n):
def die(n):
if die==1:
f1+=1
elif die==2:
f2+=1
elif die==3:
f3+=1
elif die==4:
f4+=1
elif die==5:
f5+=1
else:
f6+=1
x=random.randint(1,6)
die(x)
print("die1: " +f1+"die2: " +f2+"die3: " +f3+ "die4: " +f4+"die5: " +f5+"die6: " +f6)

Answer 1

... allow me to introduce some changes to your code.

import random

# instead of using separate variables as counter, let's use a list!

counter = [0,0,0,0,0,0]

n = int(input())
for i in range(0,n):
counter[random.randint(1,6)-1]+=1

# we find the max counter
mode = max(counter)

# and we find which number the max counter belongs to

max_roll = counter.index(mode)+1

print(max_roll)

# The problem with this code though, is that it doesn't care if there are two max rolls.

Answer 2

Fermi, wow! Thank you.